短线阳起:ref(c,1)*1.03<ref(o,1) and c>o*1.03 ando>ref(l,1) andcount(c/ref(c,1)<0.95 ,8)>1 and v<ref(v,1) and ref(c,1)/ref(c,2)<0.9 and ref(c,1)*1.03<ref(o,1) ;